v^2-3v-10/4v^2-16

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Solution for v^2-3v-10/4v^2-16 equation: 


v in (-oo:+oo)

v^2-((10/4)*v^2)-(3*v)-16 = 0

v^2+(-5/2)*v^2-3*v-16 = 0

-3/2*v^2-3*v-16 = 0

DELTA = (-3)^2-(-16*(-3/2)*4)

DELTA = -87

DELTA < 0

v belongs to the empty set

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